Physics Elasticity Question 120
Question: The force required to stretch a steel wire of $ 1,cm^{2} $ cross-section to 1.1 times its length would be $ (Y=2\times 10^{11},N{{m}^{-2}}) $
[MP PET 1992]
Options:
A) $ 2\times 10^{6},N $
B) $ 2\times 10^{3},N $
C) $ 2\times {{10}^{-6}}N $
D) $ 2\times {{10}^{-7}},N $
Show Answer
Answer:
Correct Answer: A
Solution:
$ F=A\times Y\times r $ =$ 1\times {{10}^{-4}}\times 2\times 10^{11}\times 0.1=2\times 10^{6}N $
BETA
