Physics Elasticity Question 127
Question: A force of $ 10^{3} $ newton stretches the length of a hanging wire by 1 millimetre. The force required to stretch a wire of same material and length but having four times the diameter by 1 millimetre is
[MP PMT 1995]
Options:
A) $ 4\times 10^{3} $ N
B) $ 16\times 10^{3} $ N
C) $ \frac{1}{4}\times 10^{3} $ N
D) $ \frac{1}{16}\times 10^{3} $ N
Show Answer
Answer:
Correct Answer: B
Solution:
$ F=Y\times A\times \frac{l}{L} $
Therefore $ F\propto r^{2} $ (Y,l and L are constant) If diameter is made four times then force required will be 16 times. i.e. 16 × 103 N
BETA
