Physics Two Dimensional Motion Question 269
Question: A motor cyclist moving with a velocity of 72 km/hour on a flat road takes a turn on the road at a point where the radius of curvature of the road is 20 meters. The acceleration due to gravity is 10 m/sec2. In order to avoid skidding, he must not bend with respect to the vertical plane by an angle greater than
[CPMT 1986]
Options:
A) $ \theta ={{\tan }^{-1}}6 $
B)$ \theta ={{\tan }^{-1}}2 $
C) $ \theta ={{\tan }^{-1}}25.92 $
D)$ \theta ={{\tan }^{-1}}4 $
Show Answer
Answer:
Correct Answer: B
Solution:
$ v=72,km/hour=20,m/\sec $
$ \theta ={{\tan }^{-1}}( \frac{v^{2}}{rg} )={{\tan }^{-1}}( \frac{20\times 20}{20\times 10} )={{\tan }^{-1}}(2) $
BETA
