Physics Two Dimensional Motion Question 274
Question: A road is 10 m wide. Its radius of curvature is 50 m. The outer edge is above the lower edge by a distance of 1.5 m. This road is most suited for the velocity
Options:
A) 2.5 m/sec B)4.5 m/sec C) 6.5 m/sec D)8.5 m/sec
Show Answer
Answer:
Correct Answer: D
Solution:
$ \frac{v^{2}}{rg}=\frac{h}{l} $
Therefore $ v=\sqrt{\frac{rgh}{l}} $
$ =\sqrt{\frac{50\times 1.5\times 9.8}{10}}=8.57,m/s $
BETA
