Physics Two Dimensional Motion Question 328
Question: A particle moves with constant speed v along a circular path of radius r and completes the circle in time T. The acceleration of the particle is
[Orissa JEE 2002]
Options:
A) $ 2,\pi ,v/T $ B)$ 2,\pi ,r/T $ C) $ 2,\pi ,r^{2}/T $ D) $ 2,\pi ,v^{2}/T $
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Answer:
Correct Answer: A
Solution:
Acceleration$ ={{\omega }^{2}}r=\frac{v^{2}}{r}=\omega v=\frac{2\pi }{T}v $
BETA
