Physics Two Dimensional Motion Question 333
Question: A proton of mass 1.6 × 10?27 kg goes round in a circular orbit of radius 0.10 m under a centripetal force of 4 × 10?13 N.then the frequency of revolution of the proton is about
[Kerala (Med.) 2002]
Options:
A) 0.08 × 108 cycles per sec B) 4 × 108 cycles per sec C) 8 × 108 cycles per sec D) 12 × 108 cycles per sec
Show Answer
Answer:
Correct Answer: A
Solution:
$ m,4{{\pi }^{2}}n^{2}r=4\times {{10}^{-13}} $
Therefore $ n=0.08\times 10^{8},cycles/\sec . $
BETA
