Physics Two Dimensional Motion Question 338
Question: A person with his hands in his pockets is skating on ice at the velocity of 10 m/s and describes a circle of radius 50 m. What is his inclination with vertical
[Pb. PET 2000]
Options:
A) $ \frac{\sqrt{3}}{2}. $ B)$ {{\tan }^{-1}}( \frac{3}{5} ) $ C) $ {{\tan }^{-1}}(1) $ D) $ {{\tan }^{-1}}( \frac{1}{5} ) $
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Answer:
Correct Answer: D
Solution:
The inclination of person from vertical is given by, $ \tan \theta =\frac{v^{2}}{rg}=\frac{{{(10)}^{2}}}{50\times 10}=\frac{1}{5} $ \ $ \theta ={{\tan }^{-1}}(1/5) $
BETA
