Physics Two Dimensional Motion Question 339
Question: If the radius of curvature of the path of two particles of same masses are in the ratio 1 : 2, then in order to have constant centripetal force, their velocity, should be in the ratio of
[Pb. PET 2000]
Options:
A) 1 : 4 B) 4 : 1 C) $ \sqrt{2},,:,,1 $ D) $ 1,,:,,\sqrt{2} $
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Answer:
Correct Answer: D
Solution:
The centripetal force, $ F=\frac{mv^{2}}{r} $
Therefore $ r=\frac{mv^{2}}{F} $ \ $ r\propto v^{2} $ or $ v\propto \sqrt{r} $ (If m and F are constant),
Therefore $ \frac{v _{1}}{v _{2}}=\sqrt{\frac{r _{1}}{r _{2}}}=\sqrt{\frac{1}{2}} $
BETA
