Physics Two Dimensional Motion Question 352
Question: A stone ties to the end of a string $ 1m $ long is whirled in a horizontal circle with a constant speed. If the stone makes 22 revolution in 44 seconds, what is the magnitude and direction of acceleration of the stone
[CBSE PMT 2005]
Options:
A) $ \frac{{{\pi }^{2}}}{4}m{{s}^{-2}} $ and direction along the radius towards the centre B) $ {{\pi }^{2}}m{{s}^{-2}} $ and direction along the radius away from the centre C) $ {{\pi }^{2}}m{{s}^{-2}} $ and direction along the radius towards the centre D) $ {{\pi }^{2}}m{{s}^{-2}} $ and direction along the tangent to the circle
Show Answer
Answer:
Correct Answer: C
Solution:
a $ =\frac{v^{2}}{r}={{\omega }^{2}}r $
$ =4{{\pi }^{2}}n^{2}r=4{{\pi }^{2}}{{( \frac{22}{44} )}^{2}}\times 1 $
$ ={{\pi }^{2}},m/s^{2} $ and its direction is always along the radius and towards the centre.
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