Physics Two Dimensional Motion Question 203
Question: The length of second’s hand in a watch is 1 cm. The change in velocity of its tip in 15 seconds is:
Options:
A) zero B) $ \frac{\pi }{30\sqrt{2}}\text{ cm/s} $ C) $ \frac{\pi }{30}\text{ cm/s} $ D)$ \frac{\pi \sqrt{2}}{30}\text{ cm/s} $
Show Answer
Answer:
Correct Answer: D
Solution:
[d] $ \Delta \text{v}=\sqrt{2}v=\sqrt{2}\omega ,\text{r}=\sqrt{2}( \frac{2\pi }{60} )\times 1=\frac{\pi \sqrt{2}}{30},cm\text{/}s $
BETA
