Physics Two Dimensional Motion Question 124
Question: Two balls are projected at an angle $ \theta $ and $ (90{}^\circ -\theta ) $ to the horizontal with the same speed. The ratio of their maximum vertical heights is B Tricky
Options:
A) 1:1 B)$ \text{tan}\theta :1 $ C) $ 1:\text{tan}\theta $ D)$ \text{ta}{{n^{2}}\theta :1 $
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Answer:
Correct Answer: D
Solution:
[d] $ \frac{{{\text{H}} _{\text{1}}}}{{{\text{H}} _{\text{2}}}}\text{=}\frac{{{u^{2}}{{\sin }^{2}}\theta /\text{2g}}{{{u^{2}}{{\sin }^{2}}( 90{}^\circ -\theta)/2\text{g}}={{\tan }^{2}}\theta $
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