Physics Two Dimensional Motion Question 53
Question: An aeroplane moving horizontally with a speed of 720 km/h drops a food pocket, while flying at a height of 396.9 m.the time taken by a food pocket to reach the ground and its horizontal range is (Take g = 9.8 m/sec2)
[AFMC 2001]
Options:
A) 3 sec and 2000 m B) 5 sec and 500 m C) 8 sec and 1500 m D) 9 sec and 1800 m
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Answer:
Correct Answer: D
Solution:
$ t=\sqrt{\frac{2h}{g}}=\sqrt{\frac{2\times 396.9}{9.8}}\tilde{-}9,\sec $ and$ u=720,km/hr=200,m/s $ $ R=u\times t=200\times 9=1800,m $
BETA
