Physics Two Dimensional Motion Question 59
Question: A man standing on the roof of a house of height $ h $ throws one particle vertically downwards and another particle horizontally with the same velocity u. The ratio of their velocities when they reach the earth’s surface will be
Options:
A) $ \sqrt{2gh+{u _{^{^{{}}}}}^{2}},:u $ B) $ 1:2 $ C) $ 1:1 $ D) $ \sqrt{2gh+u^{2},}:\sqrt{2gh} $
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Answer:
Correct Answer: C
Solution:
[c] When particle is thrown in vertical downward direction with velocity u, then the final velocity at the ground level is $ v^{2}=u^{2}+2gh $
$ \
Therefore v=\sqrt{u^{2}+2gh} $ Another particle is thrown horizontally with same velocity then at the surface of earth. Horizontal component of velocity $ v _{x}=u $
Therefore, resultant velocity, $ v=\sqrt{u^{2}+2gh} $ For both the particles, final velocities when they reach the earth’s surface are equal.
BETA
