Physics Two Dimensional Motion Question 60
A particle is projected from point $ O $ with velocity $ u $ in a direction making an angle $ \alpha $ with the horizontal. At any instant its position is at point $ p $ at right angles to the initial direction of projection, Its velocity at point $ p $ is
Options:
A) $ u\tan \alpha $ B) $ u\cot \alpha $ C) $ \sec\alpha $ D) $ u\sec{\alpha} $
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Answer:
Correct Answer: B
Solution:
Horizontal velocity at point ‘[O’=u cos$ \alpha $ Horizontal velocity at point ‘P’=u sin $ \alpha $ In projectile motion horizontal component of velocity remains constant throughout the motion $
Therefore v\sin \alpha =u\cos \theta
$ \Rightarrow v=u\cot \alpha $
BETA
