Physics Two Dimensional Motion Question 76
Question: A particle is moving on a circular path of radius r with uniform velocity v. The change in velocity when the particle moves from $ P $ to $ Q $ is $ (\angle POQ={{40}^{{}^\circ }}) $
Options:
A) $ 2v,\cos ,40{}^\circ $ B) $ 2v,\sin 40{}^\circ $ C) $ 2v,\sin ,20{}^\circ $ D) $ 2v,\cos ,20{}^\circ $
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Answer:
Correct Answer: C
Solution:
[c] Change in velocity =$ 2v\sin (\theta /2)=2vsin20{}^\circ $
BETA
