Physics Two Dimensional Motion Question 129
Question: Let $ \overrightarrow{C}=\overrightarrow{A}+\overrightarrow{B} $ then
Options:
A) $ |\overrightarrow{C}| $ is always greater than $ |\overrightarrow{A}| $ B) it is possible to have $ |\overrightarrow{C}|,<,|\overrightarrow{A}| $ and$ |\overrightarrow{C}|,,<,,|\overrightarrow{B}| $ C) $ \overrightarrow{C} $ is always equal to $ \overrightarrow{A}+\overrightarrow{B} $ D) $ \overrightarrow{C} $ is never equal to $ \overrightarrow{A}+\overrightarrow{B} $
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Answer:
Correct Answer: B
Solution:
[b] As $ \overrightarrow{C}=\overrightarrow{A}+\overrightarrow{B} $ and $ |\overrightarrow{C}|,<,|\overrightarrow{B}| $
$ \
Therefore ,,,,,|\overrightarrow{C}|,<,|\overrightarrow{A}| $
BETA
