Physics Two Dimensional Motion Question 95
Question: The tension in the string revolving in a vertical circle with a mass$ m $ at the end which is at the lowest position
[EAMCET (Engg.) 1995; AIIMS 2001]
Options:
A) $ \frac{mv^{2}}{r} $ B)$ \frac{mv^{2}}{r}-mg $ C) $ \frac{mv^{2}}{r}+mg $ D)$ mg $
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Answer:
Correct Answer: C
Solution:
Tension = Centrifugal force + weight $ =\frac{mv^{2}}{r}+mg $
BETA
