Physics Two Dimensional Motion Question 97
Question: A pendulum bob on a 2 m string is displaced 60o from the vertical and then released.What is the speed of the bob as it passes through the lowest point in its path
[JIPMER 1999]
Options:
A) $ \sqrt{2},,m/s $ B) $ \sqrt{9.8},,m/s $ C) 4.43 m/s D)$ 1/\sqrt{2},,m/s $
Show Answer
Answer:
Correct Answer: C
Solution:
$ v=\sqrt{2gl(1-\cos \theta )}=\sqrt{2\times 9.8\times 2(1-\cos 60{}^\circ )} $
$ =4.43,m/s $
BETA
