Physics Two Dimensional Motion Question 98
Question: A fan is making 600 revolutions per minute.If after some time it makes 1200 revolutions per minute, then increase in its angular velocity is
[BHU 1999]
Options:
A) $ 10,\pi ,rad/\sec $ B)$ 20,\pi ,rad/\sec $ C) $ 40,\pi ,rad/\sec $ D)$ 60,\pi ,rad/\sec $
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Answer:
Correct Answer: B
Solution:
Increment in angular velocity $ \omega =2\pi (n _{2}-n _{1}) $
$ \omega =2\pi (1200-600)\frac{rad}{min}=\frac{2\pi \times 600}{60}\frac{rad}{s} $
$ =20\pi \frac{rad}{s} $
BETA
