Physics Two Dimensional Motion Question 137
Question: The condition for $ \overrightarrow{A}+\overrightarrow{B} $ to be perpendicular to $ \overrightarrow{A}-\overrightarrow{B} $ is that
Options:
A) $ |\overrightarrow{A}|,,=,,|\overrightarrow{B}| $ B)$ \overrightarrow{\text{A}},,\text{=},,\overrightarrow{\text{B}} $ C) $ \overrightarrow{\text{B}}\text{ =},,\text{0 }!!~!! $ D)$ !!|!!,\overrightarrow{\text{A}},\text{+},\overrightarrow{\text{B}},!!|!!,,\text{= }!!|!!,\overrightarrow{\text{A}}-\overrightarrow{\text{B}},,!!|!! $
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Answer:
Correct Answer: A
Solution:
[a] $ \text{(\vec{A}+\vec{B})}\text{.(\vec{A}}-\text{\vec{B})}=0 $ or $ \vec{A},\text{.},\text{\vec{A}+\vec{B}},\text{.},\vec{A}-\vec{A},\text{.},\vec{B}-\vec{B},\text{.},\vec{B}=0 $
$ \
Therefore ,,,\text{A=B}\text{.} $
BETA
