Physics Two Dimensional Motion Question 148
Question: $ \overrightarrow{a}=3,\hat{i}-5\hat{j} $ and $ \overrightarrow{b}=6,\hat{i}+3,\hat{j} $ are two vectors and $ \overrightarrow{c} $ is a vector such that $ \overrightarrow{c}=\overrightarrow{a}\times \overrightarrow{b} $ then $ |\overrightarrow{a}|:|\overrightarrow{b}|:|\overrightarrow{c}| $
Options:
A) $ \sqrt{34}:\sqrt{45}:\sqrt{39} $ B)$ \sqrt{34}:\sqrt{45}:39 $ C) $ 34:39:45 $ D)$ 39:35:34 $
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Answer:
Correct Answer: B
Solution:
[b] We have $ \vec{a}\times \vec{b}=39,\vec{k}=\vec{c} $
$ \text{Also}!!|!!\vec{a}!!|!!\text{ =},,\sqrt{34},|\vec{b}|,=\sqrt{45},\text{}!!|!!\vec{c}!!|!!\text{ =},\text{39 ;} $
$ \
Therefore !!|!!\vec{a}!!|!!\text{ :}|\vec{b}|\text{: }!!|!!\vec{c}!!|!!=\sqrt{34}:\sqrt{45}:39. $
BETA
