Physics Two Dimensional Motion Question 155
Question: The range of a projectile is R when the angle of projection is $ 40{}^\circ $ . For the same velocity of projection and range, the other possible angle of projection is
Options:
A) $ 45{}^\circ $ B)$ 50{}^\circ $ C) $ 60{}^\circ $ D)$ 40{}^\circ $
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Answer:
Correct Answer: B
Solution:
[b] Horizontal range R =$ \frac{{{u^{2}}\sin 2\theta }{\text{g}} $ . Range is same for angle of projection $ \theta $ and $ (90{}^\circ -\theta ). $