Physics Two Dimensional Motion Question 157
Question: The equation of a projectile is $ y=\sqrt{3}x-\frac{\text{g}{{x^{2}}}{20} $ The angle of projection is given by
Options:
A) $ \text{tan}\theta ,\text{=}\frac{1}{\sqrt{3}} $ B)$ \text{tan}\theta ,\text{=},\sqrt{3} $ C)$ \frac{\pi }{2} $ D) zero.
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Answer:
Correct Answer: B
Solution:
[b] Comparing the given equation with $ y=x\tan \theta -\frac{\text{g}{{x^{2}}}{2{{u^{2}}{{\cos }^{2}}\theta },\text{ we get} $
$ \text{tan}\theta ,,\text{=},\sqrt{3} $
BETA
