Physics Two Dimensional Motion Question 164
Question: A boy can throw a stone up to a maximum height of 10 m. The maximum horizontal distance that the boy can throw the same stone up to will be
Options:
A) 20$ \sqrt{2} $ m B)10 m C) 10$ \sqrt{2} $ m D) 20 m
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Answer:
Correct Answer: D
Solution:
[d] $ \text{R},,\text{=},,\frac{{{u^{2}}{{\sin }^{2}}\theta }{g},\text{ H},,\text{=},,\frac{{{u^{2}}{{\sin }^{2}}\theta }{2g} $
$ {{\text{H}} _{\max }}\text{ at 2}\theta ,,\text{=},,\text{90}{}^\circ \text{ So, }{{\text{H}} _{\max }}=\frac{{{u^{2}}}{\text{2g}} $
$ \frac{{{u^{2}}}{\text{2g}}=10\Rightarrow {{u^{2}}=10g\times 2 $
$ R=\frac{{{u^{2}}\sin 2\theta }{g}\Rightarrow {R _{\max }}=\frac{{{u^{2}}}{\text{2g}}=20\text{ meter}\text{.} $
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