Physics Two Dimensional Motion Question 169
Question: A projectile is thrown at an angle of $ 40{}^\circ $ with the horizontal and its range is $ R _{1} $ . Another projectile is thrown at an angle $ 40{}^\circ $ with the vertical and its range is $ R _{2} $ . What is the relation between $ R _{1} $ and $ R _{2} $ ?
Options:
A) $ R _{1}=R _{2} $ B)$ R _{1}=2R _{2} $ C) $ 2R _{1}=R _{2} $ D)$ R _{1}=4R _{2}/5 $
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Answer:
Correct Answer: A
Solution:
[a] R is same for both $ \theta $ and $ (90{}^\circ -\theta ). $ If angle w.r.t. Vertical is $ 40{}^\circ $ then w.r.t horizontal direction it will be $ 90{}^\circ -40{}^\circ =50{}^\circ $ .
BETA
