Physics Two Dimensional Motion Question 188
Question: A particle P is projected from a point on the surface of smooth inclined plane (see figure). Simultaneously another particle Q is released on the smooth inclined plane from the same position. P and Q collide on the inclined plane after $ t=4 $ second. The speed of projection of P is
Options:
A) 5 m/s B)10 m/s C) 15 m/s D)20 m/s
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Answer:
Correct Answer: B
Solution:
[b] It can be observed from figure that P and Q shall collide if the initial component of velocity of P on inclined plane i.e., along incline $ {u _{,\text{I},\text{I}}}=0 $ that is particle is projected perpendicular to incline. Time of flight on an inclined plane of inclination $ \alpha $ is given by $ \text{T=}\frac{2\text{u sin}( \theta -\alpha)}{\text{g}\cos \alpha } $ $ \Rightarrow 4=\frac{2\text{u sin90}{}^\circ }{10\times \frac{1}{2}}\Rightarrow \text{u= 10 m/s} $ .
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