Physics Two Dimensional Motion Question 239
Question: Referring to the above two questions, the acceleration due to gravity is given by
Options:
A) $ 10,m/{{\sec }^{2}} $ B) $ 5m/{{\sec }^{2}} $ C) $ 20,,m/{{\sec }^{2}} $ D) $ 2.5,,m/{{\sec }^{2}} $
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Answer:
Correct Answer: A
Solution:
[a] $ a _{x}=\frac{d}{dt}(v _{x})=0 $ , $ a _{y}=\frac{d}{dt}(v _{y})=-10\ m/s^{2} $ \ Net acceleration a =$ \sqrt{a _{x}^{2}+a _{y}^{2}} $ =$ \sqrt{0^{2}+10^{2}} $ =10m/s2
BETA
