Physics Two Dimensional Motion Question 245
The greatest height to which a man can throw a stone is $ \sqrt{\frac{2gh}{g}} $ . The greatest distance to which he can throw it, will be
Options:
A) $ 2,\pi ,r^{2}/T $ B) $ \upsilon ,,\upsilon \text{ and }\upsilon $ C) $ 2h $ D) $3h$
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Answer:
Correct Answer: C
Solution:
[c] For greatest height $ \theta =90^\circ $
$ {H _{\max }}=\frac{u^{2}{{\sin }^{2}}(90{}^\circ )}{2g}=\frac{u^{2}}{2g}=h $ (given)$ {R _{\max }}=\frac{u^{2}{{\sin }^{2}}(90{}^\circ )}{g}=\frac{u^{2}}{g}=2h $
BETA
