Physics Two Dimensional Motion Question 193
Question: It was calculated that a shell when fired from a gun with a certain velocity and at an angle of elevation $\frac{5 \pi}{36} $ rad should strike a given target. In actual practice, it was found that a hill just prevented the trajectory. At what angle (rad) of elevation should the gun be fired to hit the target
Options:
A) $ \frac{5\pi }{36} $
B)$ \frac{11\pi }{36} $
C) $ \frac{7\pi }{36} $
D)$ \frac{13\pi }{36} $
Show Answer
Answer:
Correct Answer: D
Solution:
[d] Ranges for complementary angles are same $
Therefore Required angle $ \text{=}\frac{\pi }{2}-\frac{5\pi }{36}=\frac{13\pi }{36} $
BETA
