Properties Of Solids And Liquids Question 393
Question: 500 g of water and 100 g of ice at $ 0{}^\circ C $ are in a calorimeter whose water equivalent is 40 g. 10 g of steam at $ 100{}^\circ C $ is added to it. Then water in the calorimeter is : (Latent heat of ice =80 cal/g, Latent heat of steam =540 cal/ g)
Options:
A) 580 g
B) 590 g
C) 600 g
D) 610 g
Show Answer
Answer:
Correct Answer: B
Solution:
[b] As 1g of steam at $ 100{}^\circ C $ melts 8g of ice, 10g of steam will melt $ 8\times 10g $ of ice at $ 0{}^\circ C $ Water in calorimeter =500 + 80+10g=590g
BETA
