Properties Of Solids And Liquids Question 400

The coefficient of apparent expansion of mercury in a glass vessel is $ 153\times {{10}^{-6}}/{}^\circ C $ and in a steel vessel is $ 144\times {{10}^{-5}}/{}^\circ C $ . If α for steel is $ 12\times {{10}^{-6}}/{}^\circ C $ , then that of glass is

Options:

$

$

B) $ 6\times {{10}^{-6}}/{}^\circ C $

C) (c)$ 36\times {{10}^{-6}}/{}^\circ C $

D) $ 27\times {{10}^{-6}}/{}^\circ C $

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Answer:

Correct Answer: A

Solution:

$ {\gamma _{real}}={\gamma _{app}}+{\gamma _{vessel}} $ So $ {{( {\gamma _{app}}+{\gamma _{vessel}} )} _{glass}}={{( {\gamma _{app}}+{\gamma _{vessel}} )} _{steel}} $

$ \Rightarrow 153\times {{10}^{-6}}+{{( {\gamma _{vessel}} )} _{glass}} $

$ =144\times 1{{0}^{-6}}+{{( {\gamma _{vessel}} )} _{steel}} $

$ Further{{({\gamma _{vessel}})} _{steel}}=3\alpha =3\times (12\times 10^{-6}}) $

$ =36\times {{10}^{-6}}^{\circ}C $

$ \Rightarrow 153\times 10^{-6}+{{( {\gamma _{vessel}} )} _{glass}} $

$ =144\times 1{{0}^{-6}}+36\times 1{{0}^{-6}} $

$ {{( {\gamma _{vessel}} )} _{glass}}=3\alpha =27\times 10^{-1}{}^{o}C $

$ \Rightarrow a=9\times {{10}^{-6}}/{}^\circ C $



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