Properties Of Solids And Liquids Question 428
Question: A lead bullet strikes against a steel plate with a velocity $ 200 m {{s}^{-1}} $ . If the impact is perfectly inelastic and the heat produced is equally shared between the bullet and the target, then the rise in temperature of the bullet is (specific heat capacity of lead $ =125Jk{{g}^{-l}}{{K}^{-l}} $ )
Options:
A) $ 80{}^\circ C $
B) $ 60{}^\circ C $
C) $ 160{}^\circ C $
D) $ 40{}^\circ C $
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Answer:
Correct Answer: A
Solution:
[a] Heat produced $ =ms\Delta T =\frac{1}{2}( \frac{1}{2}mv^{2} ) $
$ \Rightarrow \Delta T=\frac{v^{2}}{4s}=\frac{{{(200)}^{2}}}{4\times 125}=\frac{4\times 10^{4}}{4\times 125}={{80}^{o}}C $
BETA
