Properties Of Solids And Liquids Question 433
Question: A 2 kg copper block is heated to $ 500{}^\circ C $ and then it is placed on a large block of ice at $ 0{}^\circ C $ . If the specific heat capacity of copper is $ 400 J/kg{}^\circ C $ and latent heat of fusion of water is $ 3.5\times l0^{5} J/ $ kg, the amount of ice that can melt is
Options:
A) (7/8) kg
B) (7/5) kg
C) (8/7) kg
D) (5/7) kg
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Answer:
Correct Answer: C
Solution:
[c] Let x kg of ice can melt Using law of Calorimetry, Heat lost by copper = Heat gained by ice $ 2\times 400\times (500-0)=x\times 3.5\times 10^{5} $
or $ x=\frac{2\times 400\times 500}{3.5\times 10^{5}}=\frac{8}{7}kg $
BETA
