Properties Of Solids And Liquids Question 454
Question: A container contains hot water at $ 100{}^\circ C $ . If in time $ T _{1} $ temperature falls to $ 80{}^\circ C $ and the time $ T _{2} $ temperature falls to $ 60{}^\circ C $ form $ 80{}^\circ C $ , then
Options:
A) $ T _{1}=T _{2} $
B) $ T _{1}>T _{2} $
C) $ T _{1}<T _{2} $
D) None of these
Show Answer
Answer:
Correct Answer: C
Solution:
[c] Rate of coiling$ =\frac{-d\theta }{dt}\propto ( \frac{{\theta _{1}}+{\theta _{2}}}{2}-{\theta _{0}} ) $ In second case average temperature will be less hence rate of coiling will be less. Therefore time taken will be more than 4 minutes.
BETA
