Properties Of Solids And Liquids Question 535
Question: At $ 15{}^\circ C, $ a wheel has diameter of 30 cm and inside diameter of a steel rim is 29.9 cm. Coefficient of thermal expansion of steel is $ 1.2\times {{10}^{-5}}{{/}^{o}}C $ . To what temperature, the rim must be heated so that it can slip over wheel?
Options:
A) $ 2787{}^\circ C $
B) $ 2772{}^\circ C $
C) $ 2529{}^\circ C $
D) $ 2802{}^\circ C $
Show Answer
Answer:
Correct Answer: D
Solution:
Rim will slip if its diameter increases to 30 cm. Hence $ \Delta l=0.1cm $
$ \Delta T=\frac{\Delta l}{l\times a}=\frac{0.1}{29.9\times 1.2\times {{10}^{-5}}}=2787^{o}C $
Rim to be heated to temperature
$ 2787+15=2802^{o}C $
BETA
