Properties Of Solids And Liquids Question 542
Question: A constant volume gas thermometer shows pressure reading of 50 cm and 90 cm of mercury at $ 0{}^\circ C $ and $ 100{}^\circ C $ respectively. When the pressure reading is 60 cm of mercury, the temperature is
Options:
A) $ 25{}^\circ C $
B) $ 40{}^\circ C~ $
C) $ 15{}^\circ C $
D) $ {{12.5}^{o}}C $
Show Answer
Answer:
Correct Answer: A
Solution:
$ t=\frac{( P _{1}-P _{0} )}{( P _{100}-P _{0} )}\times 100{}^\circ C $
$ =\frac{( 60-50 )}{( 90-50 )}\times 100=25{}^\circ C $
BETA
