Properties Of Solids And Liquids Question 83
Question: 300 gm of water at 25°C is added to 100 gm of ice at 0°C. The final temperature of the mixture is [MP PET 2004]
Options:
A) $ -\frac{5}{3}{}^\circ C $
B) $ -\frac{5}{2}{}^\circ C $
C) ? 5°C
0°C
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Answer:
Correct Answer: D
Solution:
$ {\theta _{\text{mix}}}=\frac{m _{W}{\theta _{W}}+\frac{{m _{i}}{L _{i}}}{S _{W}}}{{m _{i}}+m _{W}} $
$ =\frac{300\times 25-\frac{100\times 80}{1}}{100+300}=-1.25^{o}C$
Which is not possible. Hence $ {\theta _{mix}}=0^{\circ}C $
BETA
