Rotational Motion Question 110
A bar of mass $m$ length $\ell $ is in pure translational motion with its centre velocity $v$ . It collides with another identical bar which is at rest and sticks to it. Assume that after the collision it becomes one system, then the angular velocity of the system after the collision is
Options:
A) $\frac{1}{5}\frac{v}{\ell }$
B) $\frac{2}{5}\frac{v}{\ell }$
C) $\frac{3}{5}\frac{v}{\ell }$
D) $\frac{v}{\ell }$
Show Answer
Answer:
Correct Answer: C
Solution:
[c] Conservation of angular momentum of combined system about centre of mass of the system
$mg\frac{\ell }{4}=I _{com}\omega =\frac{10}{24}m{{\ell }^{2}}\omega $
$\Rightarrow \omega =\frac{3}{5}\frac{v}{\ell }$
BETA
