Rotational Motion Question 122
Question: Three identical thin rods, each of length $L$ and mass m, are welded perpendicular to one another . The assembly is rotated about an axis that passes through the end of one rod and is parallel to another. The moment of inertia of this structure about this axis is
Options:
A) $\frac{7}{12}mL^{2}$
B) $\frac{11}{14}mL^{2}$
C) $\frac{5}{15}mL^{2}$
D) $\frac{11}{12}m^{2}$
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Answer:
Correct Answer: D
Solution:
The moment of the rod about the $y$ axis is essentially zero (axis through centre, parallel to rod) because the rod is thin.
The moments of the rods on the $x$ and $z$ axes are each $I=\frac{1}{12} M L^2$ (Axis through centre, perpendicular to rod) as given in the table in the chapter.
The total moment of the three rods about the axis (and about the center of mass) is
$ I _{C M}=I _{\text {on } x \text { axis }}+I _{\text {on } y \text { axis }}+I _{\text {on } z \text { axis }}$
$ =\frac{1}{12} M L^2+0+\frac{1}{12} M L^2=\frac{1}{2} m L^2 $
For the moment of the rod-combination about the axis of rotation, the parallelaxis theorem gives
$ I=I _{C M}+3 m(\frac{L}{2})^2= \frac{1}{6}mL^2+\frac{3}{4} m L^2 $
$ =\frac{2}{12}+\frac{9}{12}m L^2=\frac{11}{12} m L^2 $
BETA
