Rotational Motion Question 127
Question: A hoop rolls on a horizontal ground without Slipping with linear speed $v$ . Speed of a particle $P$ on the circumference of the hoop at angle $\theta $ is
Options:
A) $2v\sin (\theta /2)$
B) $v\sin \theta $
C) $2v\cos (\theta /2)$
D) $v\cos \theta $
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Answer:
Correct Answer: A
Solution:
[a]
$v _{p}=\sqrt{v^{2}+v^{2}+2vv\cos (180-\theta )}$
$\Rightarrow v _{p}=\sqrt {2v^{2}1-cos\theta }$
$=2v\sin (\theta /2)$
BETA
