Rotational Motion Question 132
Question:A cube of side $a$ is placed on an inclined plane of inclination $\theta $ . What is the maximum value of 9 for which the cube will not topple?
Options:
A) $15{}^\circ $
B) $30{}^\circ $
C) $45{}^\circ $
D) $69{}^\circ $
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Answer:
Correct Answer: C
Solution:
[c] The cube will not topple until the line of action of CM passes through the cube.
That is, $\tan \theta =\frac{AX}{OX}=\frac{a/2}{a/2}$ or $\theta =45{}^\circ $
BETA
