Rotational Motion Question 179
Question: The moment of inertia of a uniform circular disc of radius ‘R’ and mass ‘M’ about an axis passing from the edge of the disc and normal to the disc is
Options:
A) $MR^{2}$
B) $\frac{1}{2}MR^{2}$
C) $\frac{3}{2}MR^{2}$
D) $\frac{3}{2}MR^{2}$
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Answer:
Correct Answer: C
Solution:
[c] M.I.
of a uniform circular disc of radius ‘R’ and mass ’ $M$ ’ about an axis passing through C.M and normal to the disc is $ I _{C.M.}=\frac{1}{2} M R^2$ From parallel axis theorem
$I_T=I _{C.M .}+M R^2=\frac{1}{2} M R^2+M R^2=\frac{3}{2} M R^2 $
BETA
