Rotational Motion Question 184
Moment of inertia of a circular wire of mass M and radius R about its diameter is $\frac{1}{4}MR^2$
Options:
A) $MR^{2}/2$
B) $MR^{2}$
C) $2MR^{2}$
D) $MR^{2}/4$
Show Answer
Answer:
Correct Answer: A
Solution:
Perpendicular axis theorem
$I _{x}+I _{y}\neq I _{z}$
$\Rightarrow I=\frac{1}{2}MR^{2}$
So
$I=\frac{MR^{2}}{2}$
BETA
