Rotational Motion Question 4
Question: Moment of inertia of a circular wire of mass M and radius R about its diameter is
[AIEEE 2002]
Options:
A) $ MR^{2}/2 $
B) $ MR^{2} $
C) $ 2MR^{2} $
D) $ MR^{2}/4 $
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Answer:
Correct Answer: A
Solution:
- [a] Moment of inertia of circular wire about its axis is $ MR^{2} $ .
Consider two diameters $ XX’ $ and $ YY’ $ moment of inertia about any of this diameter is same let us say $ l $ . From perpendicular axis theorem, $ l+l=MR^{2} $ $ l=\frac{MR^{2}}{2} $
BETA
