Thermodynamics Question 52
Question: Adiabatic modulus of elasticity of a gas is $ 2.1\times 10^{5}N/m^{2}. $ What will be its isothermal modulus of elasticity $ ( \frac{C _{p}}{C _{v}}=1.4 ) $
[UPSEAT 1999]
Options:
A) Zero
B) 100 J
C) - 50J
50J
Show Answer
Answer:
Correct Answer: D
Solution:
For adiabatic forces $ \Delta W=-\Delta U $
$ (\because \Delta Q=0) $
Therefore $ \Delta W=+50J $
BETA
