SATHEE: Thermodynamics Question 56

Thermodynamics Question 56

Question: Heat of neutralization of strong acid against strong base is constant and is equal to

[EAMCET 1980; AFMC 1989; DPMT 1991; MP PET 1999; BHU 1999; MP PMT 1995]

Options:

A) 13.7 kcal

B) 57 kJ

C) $ 5.7\times 10^{4} $ J

D) All of the above

Show Answer

Answer:

Correct Answer: D

Solution:

$ 13.7kcal=57kJ=5.7\times 10^{4}J $ .

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Thermodynamics Question 56

Question: Heat of neutralization of strong acid against strong base is constant and is equal to

Options:

Answer:

Solution:

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