Thermodynamics Question 6
The pressure and density of a diatomic gas $ (\gamma =5/7) $ change adiabatically from (P, d) to (P’, d’). If $ \frac{d’}{d}=32 $ , then $ \frac{P’}{P} $ should be
[CPMT 1982; EAMCET 2001]
Options:
A) $ \frac{24}{5} $
8
C) $ \frac{40}{3} $
D) 32 times its initial pressure
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Answer:
Correct Answer: D
Solution:
$ P{{V}^{\gamma }} $ =constant
Therefore $ \frac{P _{2}}{P _{1}}={{( \frac{V _{1}}{V _{2}} )}^{\gamma }}\Rightarrow P _{2}={{(8)}^{5/3}}P _{1}=32\ P _{1} $
BETA
