Thermodynamics Question 92
Question: The equilibrium constant of a reaction at $ 298K $ is $ 5\times {{10}^{-3}} $ and at $ 1000K $ is $ 2\times {{10}^{-5}} $ . What is the sign of $ \Delta H $ for the reaction
[Pb. CET 1998]
Options:
A) $ \Delta H=0 $
B) $ \Delta H $ is negative
C) $ \Delta H $ is positive
D) None of these
Show Answer
Answer:
Correct Answer: B
Solution:
Equilibrium constant decreases with temperature and $ \Delta H $ is also negative so it is -ve.
BETA
