Thermodynamics Question 28

Question: Helium at $ 27^{o}C $ has a volume of 8 litres. It is suddenly compressed to a volume of 1 litre. The temperature of the gas will be $ [\gamma =5/3] $ [CBSE PMT 1993; MP PMT 1999; Pb. PMT 2002]

Options:

A) $ \frac{R}{\gamma -1}(T _{2}-T _{1}) $

B) $ \frac{R}{\gamma -1}(T _{1}-T _{2}) $

C) $ R(T _{1}-T _{2}) $

D) Zero

Show Answer

Answer:

Correct Answer: A

Solution:

$ \Delta U=\Delta W=\frac{R(T _{2}-T _{1})}{(\gamma -1)} $

$ =\frac{R(T _{2}-T _{1})}{\gamma -1} $



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