Thermodynamics Question 289
Question: A Carnot engine whose efficiency is 50% has an exhaust temperature of 500 K. If the efficiency is to be 60% with the same intake temperature, the exhaust temperature must be (in K)
Options:
A) 800
B) 200
C) 400
D) 600
Show Answer
Answer:
Correct Answer: C
Solution:
[c] $ \eta =1-\frac{T _{1}}{T _{2}}\text{ or }\frac{50}{100}=1-\frac{500}{T _{1}}\Rightarrow T _{1}=1000K $
Also, $ \frac{60}{100}=1-\frac{T _{2}}{1000}\Rightarrow T _{2}=400K $
BETA
